Acidity

Acidity

Updated Apr 17, 2026

Carboxylic acids are about a million times more acidic than alcohols. Acetic acid has pKa 4.76; ethanol has pKa 16. That difference is about 11 pKa units, equal to a factor of 10¹¹ in Ka. The single reason is that the carboxylate conjugate base is stabilized by resonance, while the alkoxide conjugate base is not.

Carboxylate anion showing the negative charge delocalized equally over two equivalent oxygens via resonance
Carboxylate resonance: the negative charge is delocalized equally between the two oxygens via two equivalent resonance structures. In the true hybrid, each C-O bond has order 1.5 and each oxygen carries −½ formal charge. Credit: Wikimedia Commons, CC BY-SA

The Resonance Picture

When a carboxylic acid loses its proton (H⁺), the conjugate base has TWO equivalent resonance structures:

  1. Structure 1: R-C(=O)-O⁻. Negative charge on the oxygen that used to have the H; C=O on the other oxygen.
  2. Structure 2: R-C(-O⁻)=O. Negative charge on the oxygen that was C=O; the former C-OH becomes a double bond.

These two structures are equivalent (same energy, same connectivity), so the real carboxylate anion is a 50:50 hybrid. The negative charge is distributed equally between the two oxygens, and both C-O bonds are equivalent (bond order 1.5).

Why This Makes Carboxylic Acids Strong Acids

The alkoxide anion from an alcohol (RCH₂-O⁻) has the negative charge on ONE oxygen with no resonance partner. Its energy is higher than a resonance-delocalized anion.

The carboxylate anion (RCOO⁻) spreads the same negative charge over TWO equivalent oxygens. Charge delocalization always reduces energy. The more atoms sharing a charge, the more stable the anion.

Quantifying the effect: carboxylate’s resonance stabilization is about 30-40 kJ/mol, which corresponds to about 10¹¹ in Ka. The observed pKa difference (16 - 4.8 ≈ 11) matches perfectly.

Comparison with Phenols

Phenols (aromatic ring -OH) have pKa ~10. Their conjugate base (phenoxide) delocalizes charge into the aromatic ring (4 contributing structures, hitting C2, C4, and C6 positions). Phenol is about a million times more acidic than ethanol but a million times less acidic than a typical carboxylic acid.

Why the ranking carboxylic acid > phenol > alcohol?

  • Carboxylate: 2 equivalent atoms sharing charge; both are electronegative oxygens.
  • Phenoxide: 4 atoms sharing charge; but 3 of them are carbons (less electronegative than O); only 1 is oxygen. Net effect: less stabilization than carboxylate despite more resonance partners.
  • Alkoxide: 1 atom (oxygen); no resonance.

The quality of the atoms sharing the charge matters as much as the number of atoms.

pKa Values to Memorize

SubstratepKa
Strong mineral acids (HCl, H₂SO₄)< 0
Halo-carboxylic acids (e.g., chloroacetic)2-3
Typical carboxylic acids4-5
Aliphatic amino acid alpha-COOH~2
Phenols (unsubstituted)10
Ammonium (R-NH₃⁺)9-10
Water15.7
Alcohols16-18
Terminal alkyne25
Alpha-H of ester25
Alpha-H of ketone20
Alkane~50

Anchor: carboxylic acid pKa ≈ 4-5 is a memorize-now number. It is the most common acid on the MCAT and a biological pKa benchmark.

Behavior at Physiological pH

At pH 7, a carboxylic acid with pKa 4 is about 3 pKa units above its pKa. From Henderson-Hasselbalch: 10^(7-4) = 1000-fold preference for the deprotonated form. So carboxylic acids at physiological pH are essentially 99.9% carboxylate.

This is critical in biochemistry. “Acetic acid” as metabolized by cells is really acetate; “fatty acid” in the bloodstream is fatty acid anion (bound to albumin); “lactic acid” produced in muscle is lactate. The dissociation is essentially complete under biological conditions.

Ethanol has pKa ~16; acetic acid has pKa ~5. Both have an O-H group. Explain the 11-pKa difference.
Click to reveal answer
The conjugate base of ethanol (ethoxide, CH₃CH₂O⁻) has the negative charge localized on one oxygen with no resonance delocalization. The conjugate base of acetic acid (acetate, CH₃COO⁻) has the negative charge delocalized equally over two equivalent oxygens via resonance - two equal resonance structures contribute to the hybrid. This charge delocalization stabilizes the anion by about 30 kJ/mol, which translates to an 11-pKa difference in acidity (a factor of 101110^{11} in Ka). Same O-H bond, completely different conjugate base stability.