DNA Replication

DNA Replication

5 min read Updated Apr 18, 2026

DNA replication produces two identical double helices from one original. The key experiment (Meselson-Stahl, 1958) showed that replication is semiconservative - each daughter molecule contains one original strand and one newly synthesized strand.

The replication fork, enzyme by enzyme

DNA replication
still-zipped parent duplex template · its 3' end faces the fork template · its 5' end faces the fork helicase unzips the fork topo relieves supercoiling ahead of the fork the fork travels this way RNA 5' 3' Leading strand · one continuous run, chasing the fork one primer, and polymerase III never lets go RNA RNA RNA RNA Lagging strand · Okazaki fragments, each built back away from the fork every fragment needs its own primer, so primase keeps coming back Every enzyme, in the order it acts 1 Helicase Unzips the double helix at the fork, breaking the hydrogen bonds between bases. 2 Single-strand binding protein Coats the separated strands so they cannot snap back together. 3 Topoisomerase Cuts, unwinds, and reseals ahead of the fork to relieve the supercoiling that unzipping creates. 4 Primase Lays down a short RNA primer, because DNA polymerase can only extend, never start. 5 DNA polymerase III Does the actual synthesis, 5' to 3', and proofreads as it goes with 3'→5' exonuclease activity. 6 DNA polymerase I Replaces each RNA primer with DNA using 5'→3' exonuclease activity. 7 Ligase Seals the last nick between Okazaki fragments, forming the final phosphodiester bond. The end-replication problem the last primer on the lagging strand has no upstream 3' end to replace it from, so every division loses a little. Telomeres are the sacrificial repeats that absorb it; telomerase rebuilds them in stem cells and in most cancers.
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Leading strand: continuous Lagging strand: in fragments RNA primer Parent strands
Semi-conservative, bidirectional, and always 5' to 3'. Those three constraints between them force everything else on this map: the primers, the fragments, the two polymerases, the ligase, and the fact that chromosome ends are a problem at all.

The Replication Fork

Replication begins at an origin of replication. The double helix is unwound, creating a Y-shaped replication fork. DNA polymerase synthesizes new DNA on both template strands - but each strand is made differently because of the antiparallel geometry.

  • Leading strand: synthesized continuously 5’ to 3’ toward the fork.
  • Lagging strand: synthesized discontinuously in short 5’ to 3’ fragments called Okazaki fragments. These are later joined together.

Key Enzymes

| Enzyme | Job |
|--------|-----|
| Helicase | Unwinds the double helix at the fork |
| Topoisomerase (gyrase in bacteria) | Relieves supercoiling ahead of the fork |
| Single-strand binding proteins (SSBs) | Prevent reannealing of the separated strands |
| Primase | Synthesizes short RNA primers (~10 nt) that DNA polymerase can extend |
| DNA polymerase III (bacteria) / δ, ε (eukaryotes) | Main replicative polymerase. Adds dNTPs to the 3’-OH of the growing strand |
| DNA polymerase I (bacteria) | Removes RNA primers, fills in gaps with DNA |
| DNA ligase | Seals nicks between Okazaki fragments |

Fidelity

DNA polymerases have very low error rates - about one mistake per 10710^{7} bases. Several mechanisms contribute:

  • Base selection: the active site is shaped to fit correct base pairs much better than mismatches.
  • Proofreading: most replicative polymerases have 3’ to 5’ exonuclease activity that removes a mispaired base just after it is added, then tries again.
  • Mismatch repair: post-replication, a separate system scans newly made DNA for any surviving mismatches and corrects them (see DNA repair section).

Together these systems bring the overall error rate down to about one mistake per 10910^{9} bases.

What is semiconservative DNA replication, and how was it shown experimentally?
Click to reveal answer
Each daughter DNA molecule consists of one original (“parental”) strand and one newly synthesized (“daughter”) strand. Meselson and Stahl grew E. coli in 15N (heavy nitrogen), switched to 14N (light nitrogen), and tracked the DNA density. After one round of replication, all DNA had intermediate density (one heavy strand + one light strand), consistent only with semiconservative replication.
Why must the lagging strand be synthesized discontinuously?
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DNA polymerase only adds nucleotides to a free 3’-OH, meaning it synthesizes 5’ to 3’. At the replication fork, one template is oriented so synthesis runs into the fork (continuous leading strand). The other template is oriented so 5’ to 3’ synthesis would run AWAY from the fork. The lagging strand must therefore be synthesized in short fragments (Okazaki fragments), each started with a new primer as more template is exposed. Ligase later joins them.
Why are RNA primers needed at the start of each new DNA fragment?
Click to reveal answer
DNA polymerases cannot start a new strand from scratch - they can only extend an existing 3’-OH. Primase, a specialized RNA polymerase, does not need a primer and lays down a short RNA primer on the template. DNA polymerase then extends that primer. After replication, the RNA primers are removed and replaced with DNA (by polymerase I in bacteria, or by a separate enzyme in eukaryotes).