Thermal Expansion

Thermal Expansion

Updated Mar 26, 2026

Railroad tracks buckle in the summer. Bridge decks have those strange metal teeth at each end. Sidewalk slabs are separated by gaps filled with tar. The lid on a stuck jar comes loose when you run it under hot water.

These are all solutions to (or examples of) the same problem: most materials expand when heated and contract when cooled. Engineers spend a lot of time and money managing this fact, and the MCAT expects you to know the formulas, recognize the real-world examples, and understand why it happens.

Why Materials Expand

At higher temperatures, atoms vibrate with greater amplitude around their equilibrium positions. Because the potential energy curve between atoms is asymmetric (steeper on the compression side), the average separation between atoms grows slightly. Multiply that tiny increase by billions of atoms, and you get a measurable change in size.

Linear Expansion

For a solid object with a single dominant dimension (a rod, a rail, a wire), we use the linear expansion formula:

The coefficient α is material-specific. Metals generally have larger α values than ceramics or glass. Some MCAT-relevant values:

Materialα (x 10610^{-6} /°C)
Aluminum24
Steel12
Glass9
Concrete12

Volumetric Expansion

For three-dimensional expansion (a liquid in a container, a solid block), use:

The approximation β ≈ 3α makes sense if you think about it: a cube expanding equally in all three dimensions. Each dimension grows by a factor of (1 + αΔT), so the volume grows by (1+αΔT)3(1 + \alpha\Delta T)^3 ≈ 1 + 3αΔT for small expansions.

Special Case: Water

Water is anomalous. Most liquids contract steadily as they cool, but water reaches its maximum density at 4 °C. Below 4 °C, water actually expands as it cools further and eventually freezes into ice, which is less dense than liquid water.

This is why ice floats and why lakes freeze from the top down. The densest water (4 °C) sinks to the bottom, insulating aquatic life below the ice layer.

The Hole-in-a-Plate Problem

A classic MCAT question: a metal plate with a hole is heated. Does the hole get bigger or smaller?

The hole gets bigger. Imagine the hole is filled with the same metal - if heated, that plug would expand. The surrounding material must expand the same way, so the hole expands as if it were made of the same material. Every linear dimension grows, including the diameter of the hole.

Thermal expansion of a rod showing the original length L and the change in length ΔL as temperature increases, with the expansion proportional to the original length and temperature change
Thermal expansion: a rod expands by ΔL = α times L times ΔT when heated. Every linear dimension increases, including holes in materials. Credit: Wikimedia Commons, CC BY-SA
A steel rod is 2.00 m long at 20 °C. How much does it expand when heated to 120 °C? (α_steel = 12 x 10610^{-6} /°C)
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ΔL = 0.0024 m = 2.4 mm. ΔL = αL0L_0ΔT = (12 x 10610^{-6})(2.00)(100) = 2.4 x 10310^{-3} m. The expansion is small but measurable - and over a long bridge or railroad, these millimeters add up to centimeters.
A metal ring is too small to fit over a metal sphere. Should you heat the ring or cool it to make it fit?
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Heat the ring. When heated, the ring expands - including its inner diameter. This is the same principle as the hole-in-a-plate problem: heating a ring makes the opening larger, not smaller.