Competitive Inhibition

Competitive Inhibition

5 min read Updated Apr 18, 2026

The four inhibition patterns on one pair of axes

Enzyme kinetics
Velocity against substrate the shape you measure Vmax Β½Vmax v [S] competitive uncompetitive noncompetitive One over each, plotted straight the shape you read intercepts off 1/v 1/[S] 0 y-intercept = 1/Vmax x-intercept = βˆ’1/Km Inhibitor Km Vmax Binds Competitive rises unchanged active site, free enzyme only Enough substrate out-competes it, so Vmax is still reachable. Noncompetitive unchanged falls allosteric site, E or ES equally Substrate cannot displace it, so some enzyme is simply gone. Uncompetitive falls falls ES complex only Locks substrate in place, so apparent affinity rises as activity drops. Mixed binds both forms but not equally: Vmax always falls, Km moves either way. Noncompetitive is the case where it binds both equally.
1

Scroll sideways to see the whole map.

Competitive Noncompetitive Uncompetitive No inhibitor (dashed reference)
Only three numbers ever change: where the curve saturates, where it reaches half-saturation, and whether more substrate can rescue it. Competitive is the only one substrate can out-compete, which is why it is the only one that leaves Vmax alone.

A competitive inhibitor looks enough like the real substrate to bind the active site, but it cannot be catalyzed. When the inhibitor is sitting in the active site, the enzyme cannot do its job. When a real substrate arrives, it has to wait its turn - or, if there is a lot of substrate, it just outcompetes the inhibitor.

That word β€œoutcompete” is the entire concept. Competitive inhibition can be reversed by adding more substrate. This is why Vmax does not change: with enough substrate, the enzyme still hits its full speed. Only the apparent Km goes up - it takes more substrate to reach half-Vmax because some of the substrate is being wasted fighting the inhibitor for active sites.

Effect on Km and Vmax

| Parameter | Change | Why |
|-----------|--------|-----|
| Km (apparent) | Increases | You need more substrate to reach half-Vmax because some substrate is wasted displacing inhibitor |
| Vmax | Unchanged | At infinite [S], substrate always wins; the enzyme still reaches its full speed |
| Binding site | Active site only | Inhibitor binds where substrate does |

Lineweaver-Burk Signature

On Lineweaver-Burk, competitive inhibition produces lines that all cross at the y-intercept. The y-intercept (1/Vmax) is fixed because Vmax is unchanged. The x-intercept (-1/Km) moves rightward (closer to zero), showing that Km has increased.

Real Drug Examples

Competitive inhibitors make excellent drugs because the body can flush them out, and more substrate restores normal function.

  • Statins (atorvastatin, simvastatin) competitively inhibit HMG-CoA reductase, the rate-limiting enzyme of cholesterol synthesis.
  • ACE inhibitors (lisinopril, enalapril) competitively inhibit angiotensin-converting enzyme, lowering blood pressure.
  • Methotrexate is a folate analog that competitively inhibits dihydrofolate reductase, used in cancer chemotherapy and autoimmune disease.
  • Ethanol is given as a treatment for methanol poisoning because it competes with methanol for alcohol dehydrogenase, slowing the production of toxic formaldehyde.
How does a competitive inhibitor affect Vmax and Km?
Click to reveal answer
Vmax is unchanged. Apparent Km increases. Because the inhibitor binds the active site but can be displaced by substrate, adding enough substrate still brings the enzyme to full speed - only more substrate is required to reach half-max velocity.
Methotrexate competes with folate at dihydrofolate reductase. On a Lineweaver-Burk plot with and without methotrexate, where will the two lines meet?
Click to reveal answer
They will meet on the y-axis at the same y-intercept (1/Vmax). This is the hallmark of competitive inhibition - Vmax is preserved, so the y-intercepts are identical, while the x-intercepts (reflecting Km) shift.
Why is ethanol given as a treatment for methanol poisoning?
Click to reveal answer
Ethanol competitively inhibits alcohol dehydrogenase, the same enzyme that converts methanol to toxic formaldehyde. By saturating the enzyme with ethanol, you slow methanol oxidation long enough for the body to clear it unchanged. It is a deliberate therapeutic competitive inhibition.