Binding Energy & Mass Defect

Binding Energy & Mass Defect

Updated Mar 26, 2026

Here’s a strange fact: weigh two protons and two neutrons separately. Now weigh the helium-4 nucleus they form. The nucleus weighs less than the sum of its parts.

Where did the missing mass go? It was converted into the energy that glues the nucleus together. This “missing mass” is called the mass defect, and the energy it represents — via Einstein’s E=mc2E = mc^2 — is the nuclear binding energy.

This single phenomenon is the reason nuclear reactions release millions of times more energy than chemical reactions, and it’s why atomic bombs and nuclear reactors exist.

Mass Defect

The mass defect (Δm) is the difference between the mass of the individual nucleons and the actual mass of the assembled nucleus:

E = mc2^2

Einstein’s famous equation connects the mass defect to binding energy:

A useful conversion: 1 amu of mass corresponds to 931.5 MeV of energy. This allows you to skip the c2c^2 calculation entirely - just multiply the mass defect in amu by 931.5 to get the binding energy in MeV.

Example

Helium-4 has a mass defect of about 0.0304 amu. Its binding energy is:

E = 0.0304 x 931.5 MeV/amu = 28.3 MeV

This means you would need to supply 28.3 MeV to completely disassemble a helium-4 nucleus into two free protons and two free neutrons.

Binding Energy per Nucleon

The total binding energy tells you how much energy holds the entire nucleus together, but to compare the stability of different nuclei, we need the binding energy per nucleon (BE/A). This is simply the total binding energy divided by the number of nucleons.

The Binding Energy per Nucleon Curve

Graph of binding energy per nucleon versus mass number showing a curve that rises steeply for light elements, peaks at iron-56 near 8.8 MeV per nucleon, and gradually decreases for heavier elements, with fusion on the left side and fission on the right side both moving toward the iron peak
The binding energy per nucleon curve. Iron-56 sits at the peak (~8.8 MeV/nucleon), making it the most stable nucleus. Fusion of light nuclei (left of iron) and fission of heavy nuclei (right of iron) both release energy by moving toward the iron peak. Credit: Wikimedia Commons, CC BY-SA 3.0

If you plot binding energy per nucleon (y-axis) against mass number A (x-axis), you get a curve that rises steeply for light nuclei, peaks at iron-56, and then gradually decreases for heavy nuclei.

This curve is the single most important diagram in nuclear physics for the MCAT. It explains everything:

  • Light nuclei (left of iron): have relatively low BE/A. Combining them (fusion) moves up the curve toward iron, releasing energy.
  • Heavy nuclei (right of iron): also have lower BE/A than iron. Splitting them (fission) moves toward iron from the other direction, also releasing energy.
  • Iron-56 sits at the peak: it is the most tightly bound nucleus. You cannot extract energy by either fusing or splitting iron.

Why Nuclear Reactions Release So Much Energy

Chemical reactions involve rearranging electrons and breaking/forming chemical bonds, with energies on the order of a few eV per reaction. Nuclear reactions involve rearranging nucleons and tapping into the mass defect, with energies on the order of MeV per reaction - roughly a million times more energy per event.

This enormous energy difference is why a small amount of nuclear fuel can power a city, while burning the same mass of coal would barely heat a building.

A nucleus has a mass defect of 0.5 amu. What is its binding energy in MeV?
Click to reveal answer
About 465.8 MeV. Binding energy = Δm x 931.5 MeV/amu = 0.5 x 931.5 = 465.75 MeV. This is the energy you would need to supply to completely disassemble the nucleus into individual protons and neutrons.
Why does fusing two light nuclei release energy, while fusing two iron nuclei does not?
Click to reveal answer
Light nuclei have low binding energy per nucleon. Fusing them produces a heavier nucleus with higher BE/A, and the difference is released as energy. Iron-56 already sits at the peak of the binding energy curve. Fusing two iron nuclei would produce a heavier nucleus with lower BE/A - this would require energy input rather than release it.