The Bohr Model

The Bohr Model

Updated Mar 26, 2026

Picture a ladder. You can stand on the first rung, the second rung, or the third β€” but you can’t hover between rungs. Electrons in an atom work the same way: they can only exist at specific, fixed energy levels. They can jump between levels, but they can’t sit in between.

This is the core idea behind the Bohr model, and it explains one of the most surprising facts in chemistry: atoms emit and absorb light in specific colors (discrete spectral lines), not a continuous rainbow. The colors of fireworks, the orange of a sodium street lamp, the unique fingerprint of every element on a spectrometer β€” all come from this one quantization rule.

Quantized Energy Levels

In 1913, Niels Bohr proposed that electrons in hydrogen orbit the nucleus only at certain allowed radii, each corresponding to a specific energy. These orbits are labeled by the principal quantum number n, where n = 1, 2, 3, and so on.

Key values to know:

nEnergy (eV)
1-13.6
2-3.4
3-1.51
4-0.85
infinity0 (free)

The ground state (n = 1) is the lowest energy level and the most stable. Any level above n = 1 is an excited state. The ionization energy of hydrogen - the energy needed to completely remove the electron from the ground state - is 13.6 eV.

Electron Transitions

Energy level diagram of the hydrogen atom showing electron transitions for the Lyman series (to n=1, ultraviolet), Balmer series (to n=2, visible), and Paschen series (to n=3, infrared), with arrows indicating photon emission between quantized orbits
Electron transitions in the hydrogen atom. Drops to n = 1 produce ultraviolet photons (Lyman series), drops to n = 2 produce visible light (Balmer series), and drops to n = 3 produce infrared photons (Paschen series). Larger energy gaps correspond to shorter-wavelength, higher-energy photons. Credit: Wikimedia Commons, CC BY-SA 3.0

An electron can jump between energy levels by absorbing or emitting a photon whose energy exactly matches the difference between the two levels.

  • Absorption: an electron absorbs a photon and jumps to a higher level (nlown_{\text{low}} to nhighn_{\text{high}}).
  • Emission: an electron drops to a lower level and emits a photon (nhighn_{\text{high}} to nlown_{\text{low}}).

Example Calculation

What wavelength photon is emitted when a hydrogen electron drops from n = 3 to n = 2?

Energy difference: |E3E_3 - E2E_2| = |-1.51 - (-3.4)| = 1.89 eV

Convert to joules: 1.89 eV x 1.6 x 10βˆ’1910^{-19} J/eV = 3.02 x 10βˆ’1910^{-19} J

Wavelength: Ξ» = hc / E = (6.63 x 10βˆ’3410^{-34})(3 x 10810^8) / (3.02 x 10βˆ’1910^{-19}) = 6.59 Γ—10βˆ’7\times 10^{-7} m = 659 nm

This is red light - part of the Balmer series (visible range), which we will explore in the next section.

The Heisenberg Uncertainty Principle

The Bohr model imagines electrons in neat circular orbits, but quantum mechanics tells us we cannot actually pin down an electron’s exact position and momentum at the same time.

This is not about imperfect instruments. It is a fundamental limit built into nature. An electron does not have a precise position and momentum simultaneously - it exists as a probability cloud around the nucleus.

For the MCAT, you need to understand the uncertainty principle conceptually. You will not be asked to perform calculations with it, but you should recognize that it explains why the Bohr model’s neat circular orbits are an oversimplification. Real electrons are better described by probability distributions (orbitals), which you studied in General Chemistry.

What is the energy of a hydrogen electron in the n = 3 state? How much energy is needed to ionize it from this state?
Click to reveal answer
E3E_3 = -13.69\frac{13.6}{9} = -1.51 eV. Ionization requires 1.51 eV. Ionization means bringing the electron from its current level to E = 0 (free). Since it starts at -1.51 eV, you need to add 1.51 eV to reach zero.
An electron in hydrogen absorbs a photon and jumps from n = 1 to n = 4. What is the energy of the absorbed photon?
Click to reveal answer
E = |E4E_4 - E1E_1| = |-0.85 - (-13.6)| = 12.75 eV. The photon must carry exactly the energy difference between the two levels. This is in the ultraviolet range (high energy, short wavelength).