Half-Life

Half-Life

Updated Mar 26, 2026

Imagine 1000 popcorn kernels in a hot pan. After one minute, roughly half have popped — about 500 unpopped left. Another minute, half of the remaining pop — now about 250. After another minute, ~125. Each “round” cuts the remaining count in half.

Radioactive decay works exactly the same way. After each half-life, exactly half the remaining unstable nuclei have decayed. The MCAT loves this topic because the math is dead simple (just halving), and the underlying physics ties to carbon-14 dating, drug half-lives in biology, medical imaging tracers, and any first-order kinetic process you learned about in chemistry.

Predict First

A radioactive sample has a half-life of 3 seconds. After 6 seconds (two half-lives), how much of the sample remains?

The simulation below lets you watch this process in real time. Each circle represents a single radioactive atom with an independent, random chance of decaying each moment - yet despite the randomness, the overall curve follows a smooth, predictable exponential. Hit “Start Decay” and watch the law of large numbers in action.

Half-lives: 0.00 Fraction: (1/2)^0.0 = 1.000 Atoms: 100 / 100

The Half-Life Equation

The half-life (t1/2t_{1/2}) is the time it takes for half of a radioactive sample to decay. After n half-lives, the fraction of the original sample remaining is:

The Half-Life Table

Graph showing radioactive decay over time with an exponential curve, marking successive half-lives where the remaining quantity drops from 100% to 50%, 25%, 12.5%, and so on
Radioactive decay follows an exponential curve. After each half-life, exactly half of the remaining radioactive atoms have decayed. The curve never reaches zero but approaches it asymptotically. Credit: Wikimedia Commons, CC BY-SA 3.0

This table is worth memorizing - it covers nearly every MCAT half-life question:

| Half-lives (n) | Fraction remaining | Percent remaining |
|----------------|-------------------|-------------------|
| 0 | 1 | 100% |
| 1 | 12\frac{1}{2} | 50% |
| 2 | 14\frac{1}{4} | 25% |
| 3 | 18\frac{1}{8} | 12.5% |
| 4 | 116\frac{1}{16} | 6.25% |
| 5 | 132\frac{1}{32} | 3.125% |

Solving Half-Life Problems

Step 1: Find the Number of Half-Lives

Divide the total time by the half-life: n = t / t1/2t_{1/2}

Step 2: Apply the Fraction

Multiply the initial amount by (12\frac{1}{2})^n.

Example

A sample contains 800 mg of iodine-131 (t1/2t_{1/2} = 8 days). How much remains after 24 days?

n = 24 / 8 = 3 half-lives

Amount remaining = 800 x (1/2)3(1/2)^3 = 800 x 18\frac{1}{8} = 100 mg

First-Order Kinetics

Radioactive decay is a first-order process, which means the rate of decay is proportional to the amount of radioactive material present. The more atoms you have, the more decays per second - but the fraction that decays per unit time stays constant.

This is the same first-order kinetics you learned in chemistry. The decay constant (λ) relates to the half-life:

Semi-Log Plots

On a normal (linear) graph, radioactive decay produces a curved exponential line that swoops downward. But if you plot the natural log of the amount remaining (ln N) versus time, you get a straight line with slope = -λ.

Activity

The activity of a radioactive sample is the number of decays per second, measured in becquerels (Bq) or curies (Ci). Activity follows the same half-life pattern as the number of atoms:

Activity = λ x N

Since N decreases by half each half-life, so does the activity. A freshly prepared sample is most active, and the activity drops exponentially over time.

A radioactive isotope has a half-life of 6 hours. You start with 240 mg. How much remains after 18 hours?
Click to reveal answer

30 mg. n = 186\frac{18}{6} = 3 half-lives. Amount remaining = 240 x (1/2)3(1/2)^3 = 240 x 18\frac{1}{8} = 30 mg.

A sample has decayed to 116\frac{1}{16} of its original amount. How many half-lives have passed?
Click to reveal answer

4 half-lives. (12\frac{1}{2})⁴ = 116\frac{1}{16}. Each half-life cuts the remaining amount in half: 1 to 12\frac{1}{2} to 14\frac{1}{4} to 18\frac{1}{8} to 116\frac{1}{16}.