Refraction & Snell's Law

Refraction & Snell's Law

7 min read Updated Mar 26, 2026

Stick a straw in a glass of water and look at it from the side. The straw appears to bend or break sharply at the water’s surface. Your eyes aren’t lying, and the straw isn’t actually broken — but the image of the underwater portion is in the wrong place.

Light traveling from the underwater part of the straw changes direction when it crosses from water into air. Your brain traces those bent rays backward in a straight line, so it perceives the underwater straw shifted from where it actually is. That bending of light at a boundary is refraction — and it’s the principle that makes lenses (and your eyes) able to form images.

Index of Refraction

Every transparent material slows light down by a characteristic amount. The index of refraction (nn) tells you how much:

| Material | Index of refraction (nn) |
|----------|------------------------|
| Vacuum | 1.00 (exact) |
| Air | 1.00 (effectively) |
| Water | 1.33 |
| Glass (typical) | 1.50 |
| Diamond | 2.42 |

What Causes Refraction?

When a light wave crosses from one medium into another, its speed changes but its frequency stays the same (frequency is locked in by the source — same rule from §7.1). Since v=fλv = f\lambda, if speed decreases and frequency is fixed, wavelength must shrink too. The change in speed at the boundary causes the wavefront to pivot, bending the light ray.

Snell’s Law

Light ray bending as it crosses the interface between two media of different refractive indices, with the angle of incidence and angle of refraction measured from the normal line
Snell’s law in action. A light ray bends toward the normal when entering a denser medium (higher nn), and away from the normal when entering a less dense medium. Angles and indices linked by n1sinθ1=n2sinθ2n_1 \sin\theta_1 = n_2 \sin\theta_2. Credit: Wikimedia Commons, CC BY-SA

Snell’s law is the quantitative rule for refraction. Plug in three of the four quantities and solve for the fourth.

The Two Bending Rules

You can predict the direction of bending without doing any math:

  • Entering a denser medium (nn increases): light bends toward the normal. Angle gets smaller. (“Light slows down and turns in.”)
  • Entering a less dense medium (nn decreases): light bends away from the normal. Angle gets larger. (“Light speeds up and turns out.”)
Predict First

Light passes from water (n = 1.33) into air (n = 1.00). As you keep increasing the angle of incidence, what eventually happens?

Test your prediction with the simulation below. Make n1n_1 larger than n2n_2, then drag the incident angle upward and watch the refracted ray swing away from the normal while the faint reflected ray grows stronger. Push the incident ray past the dashed critical angle marker and see where the light goes.

θ₁: 40° θ₂: 60.2° Critical angle: 47.8° Bend: away from the normal

Important Details

  • Light hitting the boundary at θ=0\theta = 0 (perpendicular) doesn’t bend. Snell’s law confirms: n1sin0=0=n2sinθ2θ2=0n_1 \sin 0 = 0 = n_2 \sin\theta_2 \Rightarrow \theta_2 = 0.
  • Frequency stays constant when light enters a new medium. Speed and wavelength change together (both decrease in a denser medium); frequency is locked in by the source.
  • The path is reversible. If light bends 30° going from air into glass, it bends 30° the other way going from glass back into air along the same line.

Worked Example

Light travels from air (n=1.00n = 1.00) into water (n=1.33n = 1.33) at an angle of incidence of 45°. Find the angle of refraction.

  • n1sinθ1=n2sinθ2n_1 \sin\theta_1 = n_2 \sin\theta_2
  • (1.00)(sin45°)=(1.33)(sinθ2)(1.00)(\sin 45°) = (1.33)(\sin\theta_2)
  • sinθ2=0.707/1.330.532\sin\theta_2 = 0.707 / 1.33 \approx 0.532
  • θ232°\theta_2 \approx 32°

Light bends toward the normal entering water (denser medium) — angle drops from 45° to 32°, exactly as the rule predicts.

Light goes from glass (n=1.50n = 1.50) into air (n=1.00n = 1.00) at an angle of incidence of 30°. What’s the angle of refraction? Does it bend toward or away from the normal?
Click to reveal answer

~48.6°, bending away from the normal. (1.50)(sin30°)=(1.00)(sinθ2)sinθ2=0.75θ248.6°(1.50)(\sin 30°) = (1.00)(\sin\theta_2) \Rightarrow \sin\theta_2 = 0.75 \Rightarrow \theta_2 \approx 48.6°. Going to a less dense medium (lower nn) → bends away from normal → larger angle.

Light has wavelength 600 nm in vacuum. What’s its wavelength in glass (n=1.50n = 1.50)?
Click to reveal answer

400 nm. In a medium with index nn: λmedium=λvacuum/n=600/1.50=400\lambda_{medium} = \lambda_{vacuum}/n = 600/1.50 = 400 nm. Frequency unchanged, but wavelength shrinks because the light slows down.

A diver underwater shines a flashlight straight up at the surface (θ=0\theta = 0). What happens to the beam as it crosses into air?
Click to reveal answer

It passes straight through with no bending. Light hitting a boundary perpendicular to the surface (θ1=0\theta_1 = 0) doesn’t refract — Snell’s law gives sin0=0\sin 0 = 0, so θ2=0\theta_2 = 0 regardless of the indices. Refraction only happens at non-zero angles.