Thin Lenses

Thin Lenses

9 min read Updated Mar 26, 2026

Hold a magnifying glass over a piece of paper in sunlight. Tilt it until the sunlight converges to a tiny, brilliant point. That point is the focal point of the lens β€” and it’s hot enough to ignite the paper.

The magnifying glass is a converging lens. The thin-lens equation that governs it is identical to the mirror equation from Β§8.7. Learn one, and you’ve learned both. The whole job of this section is teaching you to use that equation, the sign conventions, and the qualitative image rules.

Converging vs. Diverging Lenses

  • Converging lenses (convex β€” thicker in the middle) bring parallel light rays together to a focal point on the far side. Positive focal length (f>0f > 0).
  • Diverging lenses (concave β€” thinner in the middle) spread parallel light rays apart, as if from a focal point on the near side. Negative focal length (f<0f < 0).

The Thin Lens Equation

Sign Conventions for Lenses

| Quantity | Positive (+) | Negative (βˆ’) |
|----------|-------------|-------------|
| dod_o | Object on incoming-light side | Object on outgoing-light side (rare) |
| did_i | Image on outgoing-light side (real) | Image on incoming-light side (virtual) |
| ff | Converging (convex) | Diverging (concave) |
| mm | Upright | Inverted |

Interactive Lens Simulator

Predict First

An object sits far from a converging lens, forming a real, inverted image. You slide the object inward until it is closer to the lens than the focal point. What happens to the image?

Drag the object arrow to see how image position, size, and orientation change with object distance. Switch between converging and diverging lenses. Watch the three principal rays trace image formation in real time. Pay close attention to what happens as the object crosses the focal point.

do 30.0 cm
di 30.0 cm
m -1.00Γ—
Image Real
Orientation Inverted
Power 6.67 D

Converging Lens Image Cases

Converging lens ray diagram showing three principal rays converging to form a real, inverted image on the far side of the lens
Ray diagram for a converging (convex) lens. Three principal rays locate the image: parallel ray refracts through the far focal point; ray through the center passes straight; ray through the near focal point exits parallel. The intersection is the real image. Credit: Wikimedia Commons, CC BY-SA

Like concave mirrors, converging lenses produce different images depending on where the object sits:

| Object position | Image location | Image type | Orientation | Size |
|----------------|---------------|------------|-------------|------|
| Beyond 2f2f | Between ff and 2f2f (far side) | Real | Inverted | Reduced |
| At 2f2f | At 2f2f (far side) | Real | Inverted | Same size |
| Between 2f2f and ff | Beyond 2f2f (far side) | Real | Inverted | Enlarged |
| At ff | At infinity | β€” | β€” | β€” |
| Inside ff | Same side as object | Virtual | Upright | Enlarged |

Diverging Lens Images

Like convex mirrors, diverging lenses always produce the same type of image regardless of object position:

  • Virtual (same side as object, did_i negative).
  • Upright (mm positive).
  • Reduced (∣m∣<1|m| < 1).

Diverging lenses by themselves never form real images.

Lens Power in Diopters

Optometrists don’t describe eyeglass lenses by focal length β€” they use diopters.

The advantage of diopters: lens powers add simply when lenses are placed in contact. Two lenses with powers P1P_1 and P2P_2 have combined power P1+P2P_1 + P_2. This is much easier than trying to combine focal lengths directly (which involves the reciprocal mess).

An object is placed 15 cm from a converging lens with f=10f = 10 cm. Where does the image form? Describe it.
Click to reveal answer

di=+30d_i = +30 cm; real, inverted, enlarged. 1/10=1/15+1/diβ‡’1/di=1/30β‡’di=+301/10 = 1/15 + 1/d_i \Rightarrow 1/d_i = 1/30 \Rightarrow d_i = +30 cm. Positive β†’ real image on far side. m=βˆ’30/15=βˆ’2m = -30/15 = -2 β†’ inverted, 2Γ— enlarged.

A diverging lens has f=βˆ’25f = -25 cm. What is its power in diopters?
Click to reveal answer

P=βˆ’4P = -4 D. Convert ff to meters: f=βˆ’0.25f = -0.25 m. P=1/f=βˆ’4P = 1/f = -4 D. Negative confirms it’s a diverging lens.

Two thin lenses in contact have powers +2+2 D and βˆ’5-5 D. What is the combined focal length?
Click to reveal answer

fβ‰ˆβˆ’33f \approx -33 cm (diverging). Powers add: Ptotal=+2+(βˆ’5)=βˆ’3P_{total} = +2 + (-5) = -3 D. Then f=1/P=1/(βˆ’3)β‰ˆβˆ’0.33f = 1/P = 1/(-3) \approx -0.33 m = βˆ’33-33 cm. The combination acts as a diverging lens (negative net power).