Weak Acids and Bases

Weak Acids and Bases

8 min read Updated Mar 26, 2026

Most acids and bases are weak. They do not hand over all their protons or accept all available protons. Instead, they reach an equilibrium - and the position of that equilibrium is described by Ka or Kb.

Weak Acid Equilibrium

A weak acid HA partially dissociates in water:

HA + H₂O ⇌ H₃O⁺ + A⁻

The equilibrium constant for this reaction is Ka (the acid dissociation constant):

Common weak acids and their Ka values:

Weak AcidFormulaKapKa
Hydrofluoric acidHF6.8×1046.8 \times 10^{-4}3.17
Nitrous acidHNO₂4.5×1044.5 \times 10^{-4}3.35
Acetic acidCH₃COOH1.8×1051.8 \times 10^{-5}4.74
Carbonic acidH₂CO₃4.3×1074.3 \times 10^{-7}6.37
Dihydrogen phosphateH₂PO₄⁻6.2×1086.2 \times 10^{-8}7.21
Hydrocyanic acidHCN6.2×10106.2 \times 10^{-10}9.21

Weak Base Equilibrium

A weak base B accepts a proton from water:

B + H₂O ⇌ BH⁺ + OH⁻

The equilibrium constant for this reaction is Kb (the base dissociation constant):

The Relationship Between Ka, Kb, and Kw

For any conjugate acid-base pair, the product of Ka and Kb always equals Kw:

Example: Acetic acid has Ka=1.8×105K_a = 1.8 \times 10^{-5}. What is KbK_b for the acetate ion (CH₃COO⁻)?

Kb=Kw/Ka=(1.0×1014)/(1.8×105)=5.6×1010K_b = K_w / K_a = (1.0 \times 10^{-14}) / (1.8 \times 10^{-5}) = 5.6 \times 10^{-10}

This confirms that acetate is a much weaker base than acetic acid is an acid.

pKa and pKb - The Log Scale

Just as pH = -log[H⁺], we define:

  • pKa = -log(Ka) - a smaller pKa means a stronger acid
  • pKb = -log(Kb) - a smaller pKb means a stronger base

The “p” operator simply converts to a more convenient scale. An acid with Ka=105K_a = 10^{-5} has pKa=5pK_a = 5. An acid with Ka=1010K_a = 10^{-10} has pKa=10pK_a = 10. The smaller the pKapK_a, the stronger the acid.

Percent Dissociation

For weak acids, percent dissociation tells you what fraction of the acid molecules have donated their proton:

% dissociation = ([H⁺] at equilibrium / initial [HA]) x 100

Key facts about percent dissociation:

  • Diluting a weak acid increases percent dissociation (Le Chatelier’s principle - adding water shifts equilibrium right)
  • Ka does not change with dilution (it is a constant at a given temperature)
  • A stronger weak acid (larger Ka) has a higher percent dissociation at the same concentration
Ammonia (NH₃) has Kb=1.8×105K_b = 1.8 \times 10^{-5}. What is KaK_a for the ammonium ion (NH₄⁺)?
Click to reveal answer
Ka=5.6×1010K_a = 5.6 \times 10^{-10}. NH₃ and NH₄⁺ are a conjugate acid-base pair. Ka×Kb=KwK_a \times K_b = K_w, so Ka=Kw/Kb=(1.0×1014)/(1.8×105)=5.6×1010K_a = K_w / K_b = (1.0 \times 10^{-14}) / (1.8 \times 10^{-5}) = 5.6 \times 10^{-10}. The pKapK_a of NH₄⁺ is about 9.26, confirming it is a very weak acid.
Two acids: Acid A has pKa = 3.2, Acid B has pKa = 8.1. Which is the stronger acid? Which conjugate base is stronger?
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Acid A is the stronger acid (lower pKa = more dissociation). Conjugate base of Acid B is the stronger base (weaker acid = stronger conjugate base). Acid A's conjugate base has pKb = 14 - 3.2 = 10.8 (very weak base). Acid B's conjugate base has pKb = 14 - 8.1 = 5.9 (relatively stronger base).