Most acids and bases are weak. They do not hand over all their protons or accept all available protons. Instead, they reach an equilibrium - and the position of that equilibrium is described by Ka or Kb.
Weak Acid Equilibrium
A weak acid HA partially dissociates in water:
HA + H₂O ⇌ H₃O⁺ + A⁻
The equilibrium constant for this reaction is Ka (the acid dissociation constant):
Common weak acids and their Ka values:
Weak Acid
Formula
Ka
pKa
Hydrofluoric acid
HF
6.8×10−4
3.17
Nitrous acid
HNO₂
4.5×10−4
3.35
Acetic acid
CH₃COOH
1.8×10−5
4.74
Carbonic acid
H₂CO₃
4.3×10−7
6.37
Dihydrogen phosphate
H₂PO₄⁻
6.2×10−8
7.21
Hydrocyanic acid
HCN
6.2×10−10
9.21
Weak Base Equilibrium
A weak base B accepts a proton from water:
B + H₂O ⇌ BH⁺ + OH⁻
The equilibrium constant for this reaction is Kb (the base dissociation constant):
The Relationship Between Ka, Kb, and Kw
For any conjugate acid-base pair, the product of Ka and Kb always equals Kw:
Example: Acetic acid has Ka=1.8×10−5. What is Kb for the acetate ion (CH₃COO⁻)?
Kb=Kw/Ka=(1.0×10−14)/(1.8×10−5)=5.6×10−10
This confirms that acetate is a much weaker base than acetic acid is an acid.
pKa and pKb - The Log Scale
Just as pH = -log[H⁺], we define:
pKa = -log(Ka) - a smaller pKa means a stronger acid
pKb = -log(Kb) - a smaller pKb means a stronger base
The “p” operator simply converts to a more convenient scale. An acid with Ka=10−5 has pKa=5. An acid with Ka=10−10 has pKa=10. The smaller the pKa, the stronger the acid.
Percent Dissociation
For weak acids, percent dissociation tells you what fraction of the acid molecules have donated their proton:
% dissociation = ([H⁺] at equilibrium / initial [HA]) x 100
Key facts about percent dissociation:
Diluting a weak acid increases percent dissociation (Le Chatelier’s principle - adding water shifts equilibrium right)
Ka does not change with dilution (it is a constant at a given temperature)
A stronger weak acid (larger Ka) has a higher percent dissociation at the same concentration
Ammonia (NH₃) has Kb=1.8×10−5. What is Ka for the ammonium ion (NH₄⁺)?
Click to reveal answer
Ka=5.6×10−10. NH₃ and NH₄⁺ are a conjugate acid-base pair. Ka×Kb=Kw, so Ka=Kw/Kb=(1.0×10−14)/(1.8×10−5)=5.6×10−10. The pKa of NH₄⁺ is about 9.26, confirming it is a very weak acid.
Two acids: Acid A has pKa = 3.2, Acid B has pKa = 8.1. Which is the stronger acid? Which conjugate base is stronger?
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Acid A is the stronger acid (lower pKa = more dissociation). Conjugate base of Acid B is the stronger base (weaker acid = stronger conjugate base). Acid A's conjugate base has pKb = 14 - 3.2 = 10.8 (very weak base). Acid B's conjugate base has pKb = 14 - 8.1 = 5.9 (relatively stronger base).