Concentration Cells

Concentration Cells

7 min read Updated Mar 26, 2026

What if you built a cell where both electrodes were made of the same metal, dipped into solutions of the same ion at different concentrations? E° would be zero - the same half-reaction on both sides cancels perfectly. Yet the cell still produces a voltage. How?

The Concept

A concentration cell uses identical electrodes and identical ions but at different concentrations in the two half-cells. The driving force comes entirely from the concentration difference, not from a difference in reduction potentials.

The system is trying to equalize concentrations - just like how gases diffuse from high to low concentration. Nature drives toward equilibrium, and the electron flow is the mechanism.

How It Works

Consider a copper concentration cell:

  • Anode (dilute side): Cu(s) | Cu2+(0.010 M)
  • Cathode (concentrated side): Cu2+(1.0 M) | Cu(s)

At the anode (dilute side): Copper metal oxidizes to add Cu2+ ions to the dilute solution, increasing its concentration.

Cu(s) -> Cu2+(aq) + 2e-

At the cathode (concentrated side): Cu2+ ions are reduced to solid copper, decreasing the concentration.

Cu2+(aq) + 2e- -> Cu(s)

Net effect: The dilute solution gets more concentrated, and the concentrated solution gets more dilute. The system drives toward equal concentrations on both sides.

Calculating the Voltage

Since E° = 0 (identical half-reactions), the Nernst equation gives:

E = 0 - (0.0592/n)log(Q)

For the copper concentration cell with [Cu2+]dilute = 0.010 M and [Cu2+]concentrated = 1.0 M:

Q = [Cu2+]anode / [Cu2+]cathode = 0.010 / 1.0 = 0.010

E = -(0.05922\frac{0.0592}{2})log(0.010) = -(0.0296)(-2) = +0.0592 V

The voltage is small but positive, confirming the reaction is spontaneous. As the concentrations equalize, Q approaches 1, log(Q) approaches 0, and E approaches 0.

Key Features of Concentration Cells

FeatureValue
0 (identical half-reactions)
Source of voltageConcentration difference only
AnodeDilute side (metal oxidizes to increase ion concentration)
CathodeConcentrated side (ions reduce to decrease concentration)
At equilibriumBoth concentrations equal, E = 0
In a Ag/Ag+ concentration cell, one half-cell has [Ag+] = 0.001 M and the other has [Ag+] = 1.0 M. Which side is the anode?
Click to reveal answer
The dilute side (0.001 M) is the anode. The system drives toward equalization. At the dilute side, Ag metal dissolves (oxidation) to increase [Ag+]. At the concentrated side, Ag+ plates out (reduction) to decrease [Ag+]. Dilute = anode, concentrated = cathode.
Why does a concentration cell eventually stop producing a voltage?
Click to reveal answer
Because the concentrations equalize. When both half-cells reach the same concentration, Q = 1, log(Q) = 0, and E = 0. There is no more driving force. The cell reaches equilibrium because the concentration gradient - the only source of energy - has been eliminated.