A second-order reaction is one where the rate depends on the square of one reactant’s concentration, or on the product of two reactants’ concentrations. Physically, this often corresponds to a reaction that requires two molecules to collide - a bimolecular event.
Rate Law
Second-order reactions can take two forms:
When the rate law is k[A][B] with first-order dependence on each of two reactants, it suggests a collision between one molecule of A and one molecule of B as the rate-determining step.
Integrated Rate Law
For a reaction that is second order with respect to a single reactant:
Graphical Analysis
[A] vs. time: Curved (not linear). The curve decreases steeply at first, then levels off.
ln[A] vs. time: Also curved (NOT linear). This rules out first-order.
1/[A] vs. time:Straight line with slope = +k and y-intercept = 1/[A]₀.
If 1/[A] vs. t gives a straight line, the reaction is second order. Note that the slope is positive (unlike zero-order and first-order, where the slope is negative).
Determining reaction order for the dimerization of C₄H₆. Left: ln[C₄H₆] vs. time is curved, ruling out first-order. Right: 1/[C₄H₆] vs. time is linear with a positive slope equal to k, confirming second-order kinetics. Credit: OpenStax Chemistry 2e, CC BY 4.0
Half-Life
This makes intuitive sense with the dance partner analogy: as the party empties out, it takes longer and longer to find someone to dance with.
Master Comparison Table
Property
Zero Order
First Order
Second Order
Rate Law
rate = k
rate = k[A]
rate = k[A]²
Integrated Law
[A] = [A]₀ - kt
ln[A] = ln[A]₀ - kt
1/[A] = 1/[A]₀ + kt
Linear Plot
[A] vs. t
ln[A] vs. t
1/[A] vs. t
Slope of Linear Plot
-k
-k
+k
Half-Life
[A]₀ / 2k
0.693 / k
1 / (k[A]₀)
Half-Life Depends on [A]₀?
Yes (shorter each time)
No (constant!)
Yes (longer each time)
Units of k
M·s⁻¹
s⁻¹
M⁻¹·s⁻¹
A reaction has a half-life that doubles each time. What is the reaction order?
Click to reveal answer
Second order. For second-order reactions, t_(21) = 1/(k[A]₀). As [A]₀ decreases by half each half-life, the next half-life is twice as long. Only second-order kinetics show increasing half-lives.
You plot three graphs: [A] vs. t, ln[A] vs. t, and 1/[A] vs. t. The 1/[A] vs. t plot is the only one that gives a straight line. What is the reaction order, and what does the slope equal?
Click to reveal answer
Second order. The slope equals +k (positive). For second-order reactions, 1/[A] = 1/[A]₀ + kt is linear with a positive slope equal to the rate constant k.