Punnett Squares

Punnett Squares

7 min read Updated Mar 26, 2026

A Punnett square is nothing more than a multiplication table for alleles. One parent’s possible gametes go across the top. The other parent’s gametes go down the side. Each box represents one possible offspring genotype. If you can multiply, you can do genetics.

The Monohybrid Cross

A monohybrid cross examines the inheritance of a single trait. The classic example is Mendel’s flower color cross.

Cross: Pp x Pp (two heterozygous purple flowers)

Pp
PPPPp
pPppp
  • Genotypic ratio: 1 PP : 2 Pp : 1 pp (1:2:1)
  • Phenotypic ratio: 3 purple : 1 white (3:1)

The 3:1 ratio appears whenever two heterozygotes for a completely dominant trait are crossed. Memorize this ratio - it shows up constantly on the MCAT.

Monohybrid Punnett square showing a cross between two heterozygous pea plants (Pp x Pp) with 3:1 phenotypic ratio of purple to white flowers
A monohybrid cross between two heterozygous parents produces a 3:1 phenotypic ratio. Credit: OpenStax Biology 2e, CC BY 4.0

The Test Cross

What if you see a tall pea plant but do not know whether its genotype is TT or Tt? Both look the same. To find out, you perform a test cross - crossing the unknown genotype with a homozygous recessive individual (tt).

  • If the unknown is TT: all offspring are Tt (100% tall)
  • If the unknown is Tt: offspring are 50% Tt (tall) and 50% tt (short) - a 1:1 ratio

A 1:1 phenotypic ratio in a test cross tells you the unknown parent was heterozygous. Test crosses are also called back crosses.

The Dihybrid Cross

A dihybrid cross tracks two traits simultaneously. This requires a 4x4 Punnett square (16 boxes) because each parent produces four types of gametes.

Example: Cross two plants heterozygous for both flower color (Pp) and plant height (Tt).

Each parent (PpTt) can produce four gamete types: PT, Pt, pT, pt.

Dihybrid Punnett square showing a cross between two heterozygous pea plants tracking seed color and seed shape, producing a 9:3:3:1 phenotypic ratio
A dihybrid cross between two doubly heterozygous parents produces the classic 9:3:3:1 phenotypic ratio. Credit: OpenStax Biology 2e, CC BY 4.0

The resulting 16-box Punnett square gives the classic 9:3:3:1 phenotypic ratio:

  • 9 purple, tall (at least one P and one T)
  • 3 purple, short (at least one P, homozygous tt)
  • 3 white, tall (homozygous pp, at least one T)
  • 1 white, short (homozygous pp and tt)

Probability Rules

You do not always need to draw a Punnett square. Two probability rules let you solve genetics problems faster:

The Product Rule (AND): The probability of two independent events both occurring is the product of their individual probabilities.

What is the probability of a child being Pp AND Tt from a PpTt x PpTt cross?

  • P(Pp) = 24\frac{2}{4} = 12\frac{1}{2}
  • P(Tt) = 24\frac{2}{4} = 12\frac{1}{2}
  • P(Pp AND Tt) = 12\frac{1}{2} x 12\frac{1}{2} = 14\frac{1}{4}

The Sum Rule (OR): The probability of one event OR another mutually exclusive event occurring is the sum of their individual probabilities.

What is the probability of a child being homozygous (PP OR pp) from a Pp x Pp cross?

  • P(PP) = 14\frac{1}{4}
  • P(pp) = 14\frac{1}{4}
  • P(PP OR pp) = 14\frac{1}{4} + 14\frac{1}{4} = 12\frac{1}{2}

Modified Ratios to Recognize

When you see a ratio that deviates from the expected 9:3:3:1, 3:1, or 1:2:1, it signals non-Mendelian inheritance. We will cover those in the next section, but here are the key modified ratios to watch for:

Observed RatioWhat It Signals
3:1Standard monohybrid with complete dominance
1:2:1Incomplete dominance or codominance (three distinct phenotypes)
9:3:3:1Standard dihybrid with independent assortment
9:3:4Recessive epistasis (one gene masks another)
9:7Duplicate recessive epistasis
12:3:1Dominant epistasis
1:1Test cross (heterozygous x homozygous recessive)

Chi-Squared: Does the Data Fit the Expected Ratio?

MCAT passages sometimes ask whether observed offspring match a predicted Mendelian ratio. The chi-squared (χ²) goodness-of-fit test is the tool.

You will rarely compute a full χ² on the MCAT, but you may be asked to interpret a p-value. The convention: p < 0.05 rejects the predicted ratio (something non-Mendelian is going on, like linkage or selection); p β‰₯ 0.05 says the data fit.

In a dihybrid cross between two heterozygotes (AaBb x AaBb), what fraction of offspring are expected to be homozygous recessive for both traits (aabb)?
Click to reveal answer
116\frac{1}{16}. The probability of aa = 14\frac{1}{4}, and the probability of bb = 14\frac{1}{4}. Since the genes assort independently, multiply: 14\frac{1}{4} x 14\frac{1}{4} = 116\frac{1}{16}. This is the "1" in the 9:3:3:1 ratio.
You cross a purple-flowered plant of unknown genotype with a white-flowered plant (pp). All 40 offspring are purple. What is the most likely genotype of the unknown parent?
Click to reveal answer
PP (homozygous dominant). If the parent were Pp, you would expect approximately half the offspring to be white (pp). With 40 offspring all being purple, the parent is almost certainly PP. Note: you cannot be 100% certain with a test cross - there is a (12\frac{1}{2})⁴⁰ chance all 40 offspring happened to inherit P from a Pp parent, but this probability is astronomically small.