The Van 't Hoff Factor

The Van 't Hoff Factor

9 min read Updated Mar 26, 2026

Every colligative property formula has the factor “i” in it - the van ‘t Hoff factor. This single number is what makes the difference between a 1 m NaCl solution (i = 2, producing 2 mol particles) and a 1 m glucose solution (i = 1, producing 1 mol particles). Getting “i” right is essential for any colligative property calculation.

Determining i

The van ‘t Hoff factor equals the number of particles produced per formula unit of solute when dissolved:

Solute TypeExampleDissociationExpected i
Strong electrolyteNaClNa⁺ + Cl⁻2
Strong electrolyteCaCl₂Ca²⁺ + 2 Cl⁻3
Strong electrolyteFeCl₃Fe³⁺ + 3 Cl⁻4
Strong electrolyteNa₂SO₄2 Na⁺ + SO₄²⁻3
Strong electrolyteAl₂(SO₄)₃2 Al³⁺ + 3 SO₄²⁻5
Weak electrolyteCH₃COOHPartial dissociation1 < i < 2
NonelectrolyteGlucose (C₆H₁₂O₆)No dissociation1
NonelectrolyteSucroseNo dissociation1
NonelectrolyteUreaNo dissociation1

Weak Electrolytes - Partial Dissociation

Weak electrolytes like acetic acid (CH₃COOH) partially dissociate in water. If the degree of dissociation is α (where 0 < α < 1):

i = 1 + α(n - 1)

where n = the number of ions the compound would produce if it fully dissociated.

For acetic acid (n = 2) with α = 0.05 (5% dissociation):

i = 1 + 0.05(2 - 1) = 1 + 0.05 = 1.05

The van ‘t Hoff factor is just barely above 1, because very few molecules actually dissociate.

Expected vs. Measured i Values

Here is one of the most commonly tested subtleties in this chapter:

ElectrolyteExpected iMeasured i (0.10 m)Reason for Difference
NaCl2.00~1.87Ion pairing between Na⁺ and Cl⁻
MgSO₄2.00~1.21Strong ion pairing (both ions are doubly charged)
CaCl₂3.00~2.70Some Ca²⁺-Cl⁻ pairs form
Glucose1.00~1.00No dissociation, no ion pairing

Notice that MgSO₄ has an especially low measured i (1.21 vs. expected 2.00). This is because Mg²⁺ and SO₄²⁻ are both doubly charged - the electrostatic attraction between them is very strong, leading to extensive ion pairing.

Ion Pairing and Concentration

Ion pairing increases at higher concentrations because ions are closer together and more likely to encounter each other. This means:

  • At low concentrations: measured i is close to expected i
  • At high concentrations: measured i is significantly below expected i

Putting It All Together

To solve any colligative property problem:

  1. Identify the solute - strong electrolyte, weak electrolyte, or nonelectrolyte?
  2. Determine i - count the ions (strong electrolyte), use 1 (nonelectrolyte), or calculate from α (weak electrolyte)
  3. Plug into the formula - ΔTb = iKbm, ΔTf = iKfm, or π = iMRT
  4. Check for reasonableness - more particles always means a bigger effect
The expected van 't Hoff factor for MgCl₂ is 3, but the measured value in a 0.50 m solution is 2.7. Explain the discrepancy.
Click to reveal answer
Ion pairing. In solution, some Mg²⁺ and Cl⁻ ions temporarily associate, effectively behaving as a single particle rather than separate ions. This reduces the effective number of particles and lowers i below the ideal value. The relatively high concentration (0.50 m) increases the frequency of ion pairing because ions are closer together.
What is the van 't Hoff factor for Na₃PO₄ assuming complete dissociation?
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i = 4. Na₃PO₄ dissociates into 3 Na⁺ ions + 1 PO₄³⁻ ion = 4 total particles per formula unit. In practice, the measured i would be less than 4 due to ion pairing, especially given the triply-charged phosphate ion. But for MCAT calculations unless told otherwise, use the ideal value of 4.