Simple Harmonic Motion

Simple Harmonic Motion

7 min read Updated Mar 26, 2026

A child on a swing. A mass bouncing on a spring. A plucked guitar string. The atoms in a molecule vibrating against their bonds. All of these are examples of simple harmonic motion (SHM) — one of the most fundamental types of periodic motion in physics.

The MCAT tests SHM with relentless focus on two questions: what determines the period, and what does the energy do? Get these two pieces and you can answer almost any SHM question — and avoid the classic traps the exam loves to set.

What Makes Motion “Simple Harmonic”?

Simple harmonic motion happens whenever a restoring force is proportional to displacement and directed back toward the equilibrium position. Pull a mass to the right of equilibrium on a spring, and the spring pulls left. Push it to the left, the spring pushes right. The farther you displace it, the harder the spring pulls back.

Predict First

A mass on a spring is pulled twice as far from equilibrium before being released. What happens to the period of its oscillation?

Use the simulation below to watch a spring and a pendulum oscillate side-by-side. Adjust mass, spring constant, length, and gravity to see how each variable changes the period — and pay close attention to which variables surprisingly don’t matter.

Amplitude
Spring
Pendulum

Hooke’s Law

The spring is the canonical SHM system. Hooke’s law gives the restoring force:

A spring with large kk (stiff) takes a lot of force to stretch and snaps back hard. A spring with small kk (soft) stretches easily and returns gently. (Full Hooke’s law treatment in §2.5.)

Period of a Mass-Spring System

Period of a Simple Pendulum

The Critical MCAT Trap: What Does NOT Affect the Period?

This is the single most-tested SHM concept.

Energy in SHM

Simple harmonic motion represented as a sine or cosine curve, showing displacement, velocity, and acceleration as functions of time for a mass on a spring
SHM plotted over time. Displacement is sinusoidal. Velocity is maximum at equilibrium (zero displacement) and zero at the extremes. Acceleration always points opposite to displacement — the hallmark of a restoring force. Credit: Wikimedia Commons, CC BY-SA

In an ideal (frictionless) SHM system, total mechanical energy is conserved. Energy oscillates between kinetic and potential forms:

  • At maximum displacement (amplitude): all PE (PEspring=12kx2PE_{spring} = \tfrac{1}{2}kx^2 is maximum). KE = 0. Velocity = 0.
  • At equilibrium (x=0x = 0): all KE (12mv2\tfrac{1}{2}mv^2 is maximum). PE = 0. Velocity is maximum.
  • In between: mix of KE and PE, with KE+PEKE + PE = constant.

| Position | Displacement | Velocity | KE | PE |
|----------|-------------|----------|----|----|
| Maximum displacement (±A\pm A) | Maximum | 0 | 0 | Maximum |
| Equilibrium (x=0x = 0) | 0 | Maximum | Maximum | 0 |

A 2 kg mass hangs on a spring with k=200k = 200 N/m. What is the period? If the mass is replaced with 8 kg, what happens to the period?
Click to reveal answer

T0.63T \approx 0.63 s for 2 kg; T1.26T \approx 1.26 s for 8 kg. T=2πm/kT = 2\pi\sqrt{m/k}. With 2 kg: T=2π0.010.63T = 2\pi\sqrt{0.01} \approx 0.63 s. With 8 kg: T=2π0.041.26T = 2\pi\sqrt{0.04} \approx 1.26 s. Quadrupling mass doubles the period (because TmT \propto \sqrt{m}).

A pendulum has period 2 s. If the bob’s mass is doubled, what’s the new period? If the length is quadrupled, what’s the new period?
Click to reveal answer

Mass doubled: still 2 s. Pendulum period doesn’t depend on mass. Length quadrupled: 4 s. T=2πL/gT = 2\pi\sqrt{L/g}. Quadrupling LL doubles TT (4=2\sqrt{4} = 2).

A mass on a spring oscillates with amplitude AA. At what point is velocity greatest? At what point is the restoring force greatest?
Click to reveal answer

Velocity max at x=0x = 0 (equilibrium); restoring force max at x=±Ax = \pm A (extremes). Velocity peaks at equilibrium where all energy is kinetic. Force peaks at maximum displacement (since F=kxF = -kx). When one is max, the other is zero — they’re 90° out of phase.